By means of Schema.getGlobalDescribe.Values () getDescribe ().getName () can receive names of objects.With Using method getDescribe().fields.getMap() we can get fields of object. It is necessary to serialize a line which would contain all objects and their fields. How it is possible to make it?

Attribution to: Pavel

Possible Suggestion/Solution #1

Code like this:

public class Describer {
    public class Sob {
        public String name;
        public String[] fields;
    }
    public static String serialize() {
        Sob[] sobs = new Sob[] {};
        for (...) {           // Loop over SObject names
           Sob s = new Sob();
           s.name = ...;      // Get name from meta data
           s.fields = ...;    // Get field names from meta data
           sobs.add(s);
        }
        return JSON.serialize(sobs);
    }
}

would produce a JSON string that looks like this:

[{"name": "Contact", "fields": ["FirstName", "LastName", ...]}, ...]

Is that what you want or do you want a copy of all the field meta data? Or something else entirely?

Attribution to: Keith C

Possible Suggestion/Solution #2

VFP error: Attempt to de-reference a null object. Shows only 2 System.debug: debug __1 and __2

    public String getserialize(){
        Sob[] sobs = new Sob[]{};
        List<Schema.SObjectType> gd = Schema.getGlobalDescribe().Values();
        Map<String, Schema.SObjectType> gdMap = Schema.getGlobalDescribe();
        for(Schema.SObjectType f : gd){
            Sob s = new Sob();
            s.Name = (String)f.getDescribe().getName();
            System.debug('_____1' + s.Name);
            //sobs.add(s);
            Schema.Describesobjectresult dsr = gdMap.get(s.Name).getDescribe();
            Map<String, Schema.SObjectField> fieldMap = dsr.fields.getMap();
            for(String key : fieldMap.keySet()){
                System.debug('_____2' + key);
                s.Fields.add(key);
               System.debug('_____3' + key);
            }
            System.debug('_____4' + JSON.serialize(s));
            sobs.add(s);
        }
        System.debug(JSON.serialize(sobs));
        return JSON.serialize(sobs);
    }     

Attribution to: Pavel
This content is remixed from stackoverflow or stackexchange. Please visit https://salesforce.stackexchange.com/questions/31940